What is the answer to solvefor p,4p+(1-p)=p+2(1-p) ?

The answer to solvefor p,4p+(1-p)=p+2(1-p) is p= 1/4

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solvefor p,4p+(1-p)=p+2(1-p)

solve for

p, 4 p + (1 - p) = p + 2 (1 - p)

p = \frac{1}{4}

Decimal Notation

p = 0.25

Solution steps

4 p + (1 - p) = p + 2 (1 - p)

Remove parentheses:

(a) = a

4 p + 1 - p = p + 2 (1 - p)

Group like terms

4 p - p + 1 = p + 2 (1 - p)

Add similar elements:

4 p - p = 3 p

3 p + 1 = p + 2 (1 - p)

Expand

p + 2 (1 - p) : - p + 2

3 p + 1 = - p + 2

Move

1

to the right side

3 p = - p + 1

Move

p

to the left side

4 p = 1

Divide both sides by

4

p = \frac{1}{4}

M, RM = q + 4 n M

\frac{3}{5} y - 2 = 6 + \frac{1}{4} y

2 (5 x + 4) = 5 (2 x + 3) - 7

- 5 (3 x + 6) = - 3 (4 x - 2)

\frac{r}{4} = - 8

What is the answer to solvefor p,4p+(1-p)=p+2(1-p) ?
The answer to solvefor p,4p+(1-p)=p+2(1-p) is p= 1/4