What is the answer to (b-7)/3+(b+1)/5 =-1 ?

The answer to (b-7)/3+(b+1)/5 =-1 is b= 17/8

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(b-7)/3+(b+1)/5 =-1

\frac{b - 7}{3} + \frac{b + 1}{5} = - 1

b = \frac{17}{8}

Solution steps

\frac{b - 7}{3} + \frac{b + 1}{5} = - 1

Multiply by LCM

5 (b - 7) + 3 (b + 1) = - 15

Expand

5 (b - 7) + 3 (b + 1) : 8 b - 32

8 b - 32 = - 15

Move

32

to the right side

8 b = 17

Divide both sides by

8

b = \frac{17}{8}

- 29 = - 10 x + 11

- 7 x - 4 x = 8 - 2 x - 8 x

x, \frac{3}{2} x + y = 12

\frac{3}{8} = \frac{b}{2}

- 12 = 2 (2 x + 4) - (7 - 3 x)

What is the answer to (b-7)/3+(b+1)/5 =-1 ?
The answer to (b-7)/3+(b+1)/5 =-1 is b= 17/8
Solve for b: (b-7)/3+(b+1)/5 =-1
The solution is b= 17/8