What is the answer to solvefor (x+2)-5=b(x-3),x ?

The answer to solvefor (x+2)-5=b(x-3),x is x=3;\quad b\ne 1

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solvefor (x+2)-5=b(x-3),x

solve for

(x + 2) - 5 = b (x - 3), x

x = 3; b \neq = 1

Solution steps

(x + 2) - 5 = b (x - 3)

Remove parentheses:

(a) = a

x + 2 - 5 = b (x - 3)

Add/Subtract the numbers:

2 - 5 = - 3

x - 3 = b (x - 3)

Expand

b (x - 3) : b x - 3 b

x - 3 = b x - 3 b

Move

3

to the right side

x = b x - 3 b + 3

Move

b x

to the left side

x - b x = - 3 b + 3

Factor

x - b x : x (1 - b)

x (1 - b) = - 3 b + 3

Divide both sides by

1 - b; b \neq = 1

x = 3; b \neq = 1

\frac{1 0 ^{12}}{10} = 10

x, x y + 4 = 0

5 x - x = 16

- 4 q + 3 = 0

3 (1 - 3 g) = - 8 g + 14

What is the answer to solvefor (x+2)-5=b(x-3),x ?
The answer to solvefor (x+2)-5=b(x-3),x is x=3;\quad b\ne 1