What is the answer to 2x+7-2(x-1)=3(x+3) ?

The answer to 2x+7-2(x-1)=3(x+3) is x=0

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2x+7-2(x-1)=3(x+3)

2 x + 7 - 2 (x - 1) = 3 (x + 3)

x = 0

Solution steps

2 x + 7 - 2 (x - 1) = 3 (x + 3)

Expand

2 x + 7 - 2 (x - 1) : 9

Expand

3 (x + 3) : 3 x + 9

9 = 3 x + 9

Move

9

to the right side

0 = 3 x

Move

0

to the right side

= 3 x

Move

3 x

to the left side

- 3 x = 0

Divide both sides by

- 3

x = 0

\frac{4 ^{2}}{4 ^{- 1}}

\frac{18 x ( x ^{3} - 2 )}{( x ^{3} + 1 ) ^{3}} \leq 0

\frac{- 1}{2} + 1

6 x^{2} + x - 15 = 0

- 2 x^{2} \leq 4

What is the answer to 2x+7-2(x-1)=3(x+3) ?
The answer to 2x+7-2(x-1)=3(x+3) is x=0
Solve for x: 2x+7-2(x-1)=3(x+3)
The solution is x=0