What is the answer to (y-1)/2-(3y-1)/3 =2 ?

The answer to (y-1)/2-(3y-1)/3 =2 is y=-13/3

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(y-1)/2-(3y-1)/3 =2

\frac{y - 1}{2} - \frac{3 y - 1}{3} = 2

y = - \frac{13}{3}

Solution steps

\frac{y - 1}{2} - \frac{3 y - 1}{3} = 2

Multiply by LCM

3 (y - 1) - 2 (3 y - 1) = 12

Expand

3 (y - 1) - 2 (3 y - 1) : - 3 y - 1

- 3 y - 1 = 12

Move

1

to the right side

- 3 y = 13

Divide both sides by

- 3

y = - \frac{13}{3}

\frac{3 x}{4} + \frac{3 x}{2} = 54

10 x - 21 = 8 x - 7 - 12 x - 6

1.1 a = 11

- 14 = - 5 + 3 c

2 x - π = 0

What is the answer to (y-1)/2-(3y-1)/3 =2 ?
The answer to (y-1)/2-(3y-1)/3 =2 is y=-13/3
Solve for y: (y-1)/2-(3y-1)/3 =2
The solution is y=-13/3