What is the answer to (x+3)^2-(x+5)(x-2)=1 ?

The answer to (x+3)^2-(x+5)(x-2)=1 is x=-6

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(x+3)^2-(x+5)(x-2)=1

(x + 3)^{2} - (x + 5) (x - 2) = 1

x = - 6

Solution steps

(x + 3)^{2} - (x + 5) (x - 2) = 1

Expand

(x + 3)^{2} - (x + 5) (x - 2) : 3 x + 19

3 x + 19 = 1

Move

19

to the right side

3 x = - 18

Divide both sides by

3

x = - 6

- 8 + \frac{x}{7} = 16

\frac{n}{9} + 10.36 = 25.36

3.5 h + 4 = - 2

- 7 x - 17 = 2 x + 10

7 π x = - 105 π

What is the answer to (x+3)^2-(x+5)(x-2)=1 ?
The answer to (x+3)^2-(x+5)(x-2)=1 is x=-6
Solve for x: (x+3)^2-(x+5)(x-2)=1
The solution is x=-6