What is ((-35xy)^4)/((14xyz)^4) ?

The solution to ((-35xy)^4)/((14xyz)^4) is (625)/(16z^4)

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simplify ((-35xy)^4)/((14xyz)^4)

simplify

\frac{( - 35 x y ) ^{4}}{( 14 x yz ) ^{4}}

\frac{625}{16 z ^{4}}

Solution steps

\frac{( - 35 x y ) ^{4}}{( 14 x yz ) ^{4}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 35 x y)^{4} = (35 x y)^{4}

= \frac{( 35 x y ) ^{4}}{( 14 x yz ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(35 x y)^{4} = 3 5^{4} x^{4} y^{4}

= \frac{3 5 ^{4} x ^{4} y ^{4}}{( 14 x yz ) ^{4}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(14 x yz)^{4} = 1 4^{4} x^{4} y^{4} z^{4}

= \frac{3 5 ^{4} x ^{4} y ^{4}}{1 4 ^{4} x ^{4} y ^{4} z ^{4}}

Factor

3 5^{4} : 7^{4} \cdot 5^{4}

= \frac{7 ^{4} \cdot 5 ^{4} x ^{4} y ^{4}}{1 4 ^{4} x ^{4} y ^{4} z ^{4}}

Factor

1 4^{4} : 7^{4} \cdot 2^{4}

= \frac{7 ^{4} \cdot 5 ^{4} x ^{4} y ^{4}}{7 ^{4} \cdot 2 ^{4} x ^{4} y ^{4} z ^{4}}

Cancel the common factor:

7^{4}

= \frac{5 ^{4} x ^{4} y ^{4}}{2 ^{4} x ^{4} y ^{4} z ^{4}}

Cancel the common factor:

x^{4}

= \frac{5 ^{4} y ^{4}}{2 ^{4} y ^{4} z ^{4}}

Cancel the common factor:

y^{4}

= \frac{5 ^{4}}{2 ^{4} z ^{4}}

Simplify

\frac{5 ^{4}}{2 ^{4} z ^{4}} : \frac{625}{16 z ^{4}}

= \frac{625}{16 z ^{4}}

x^{2} \geq 9

∣ x + 1 ∣ \geq 5

d^{3} - 4 d^{2} + 3 d

4 x^{2} + x - 4 = 0

1.2 \cdot 5

What is ((-35xy)^4)/((14xyz)^4) ?
The solution to ((-35xy)^4)/((14xyz)^4) is (625)/(16z^4)