What is the answer to solvefor b,ax^2+bx+c=y ?

The answer to solvefor b,ax^2+bx+c=y is b=(y-ax^2-c)/x ;\quad x\ne 0

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solvefor b,ax^2+bx+c=y

solve for

b, a x^{2} + b x + c = y

b = \frac{y - a x ^{2} - c}{x}; x \neq = 0

Solution steps

a x^{2} + b x + c = y

Move

a x^{2}

to the right side

b x + c = y - a x^{2}

Move

c

to the right side

b x = y - a x^{2} - c

Divide both sides by

x; x \neq = 0

b = \frac{y - a x ^{2} - c}{x}; x \neq = 0

x, 16 r - t - x = 0

x, 9 y - 3 x = - 54

\frac{1}{2} x - 7 = 14

a, - f = 2 (a) - 5

a, g = a (4 - d^{2})

What is the answer to solvefor b,ax^2+bx+c=y ?
The answer to solvefor b,ax^2+bx+c=y is b=(y-ax^2-c)/x ;\quad x\ne 0