What is the answer to 3(x-2)+4(2-x)=x+2(x+1) ?

The answer to 3(x-2)+4(2-x)=x+2(x+1) is x=0

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3(x-2)+4(2-x)=x+2(x+1)

3 (x - 2) + 4 (2 - x) = x + 2 (x + 1)

x = 0

Solution steps

3 (x - 2) + 4 (2 - x) = x + 2 (x + 1)

Expand

2 (x + 1) : 2 x + 2

- x + 2 = x + 2 x + 2

Add similar elements:

x + 2 x = 3 x

- x + 2 = 3 x + 2

Expand

3 (x - 2) + 4 (2 - x) : - x + 2

- x + 2 = 3 x + 2

Move

2

to the right side

- x = 3 x

Move

3 x

to the left side

- 4 x = 0

Divide both sides by

- 4

x = 0

\frac{1}{4} (16 a + 40) = - a + 5 (a + 2)

\frac{2 x + 3}{5} = \frac{1}{2}

2 - 15 n = 5 (- 3 n + 2)

4 (x - 1) + 11.1 = 0.7 (x - 4)

2 x - 1 - x = - 3 x + 7

What is the answer to 3(x-2)+4(2-x)=x+2(x+1) ?
The answer to 3(x-2)+4(2-x)=x+2(x+1) is x=0
Solve for x: 3(x-2)+4(2-x)=x+2(x+1)
The solution is x=0