What is the answer to g(-2)=(-2)/(-2^2-10) ?

The answer to g(-2)=(-2)/(-2^2-10) is g=-1/(2^2+10)

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g(-2)=(-2)/(-2^2-10)

g (- 2) = \frac{- 2}{- 2 ^{2} - 10}

g = - \frac{1}{2 ^{2} + 10}

Solution steps

g (- 2) = \frac{- 2}{- 2 ^{2} - 10}

Factor

- 2^{2} - 10 : - (2^{2} + 10)

g (- 2) = \frac{- 2}{- ( 2 ^{2} + 10 )}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

g (- 2) = \frac{2}{2 ^{2} + 10}

Divide both sides by

- 2

g = - \frac{1}{2 ^{2} + 10}

x, 6 x - 2 y + 3 = 0

- x - 12 = - 5

r = 2!

6 k - 3 = 2 k + 13

x, 6 x - 3 y + 12 = 0

What is the answer to g(-2)=(-2)/(-2^2-10) ?
The answer to g(-2)=(-2)/(-2^2-10) is g=-1/(2^2+10)
Solve for g: g(-2)=(-2)/(-2^2-10)
The solution is g=-1/(2^2+10)