What are the solutions to the equation 6x-3x^2=-12 ?

The solutions to the equation 6x-3x^2=-12 are x=1-sqrt(5),x=1+sqrt(5)

Find the zeros of 6x-3x^2=-12

The zeros of 6x-3x^2=-12 are x=1-sqrt(5),x=1+sqrt(5)

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6 x - 3 x^{2} = - 12

x = 1 - 5, x = 1 + 5

Decimal Notation

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

6 x - 3 x^{2} = - 12

Move

12

to the left side

6 x - 3 x^{2} + 12 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 12}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 12 = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 5}{2 ( - 3 )}

x = \frac{- 6 + 6 5}{2 ( - 3 )} : 1 - 5

x = \frac{- 6 - 6 5}{2 ( - 3 )} : 1 + 5

The solutions to the quadratic equation are:

x = 1 - 5, x = 1 + 5

\frac{3 π}{4} + \frac{π}{4}

4.603 y - 1.842 = - 3.651 y

b^{2} - 7 b + 10

(- 4 - 2 i)^{3}

0.99 \leq e^{- n}

What are the solutions to the equation 6x-3x^2=-12 ?
The solutions to the equation 6x-3x^2=-12 are x=1-sqrt(5),x=1+sqrt(5)
Find the zeros of 6x-3x^2=-12
The zeros of 6x-3x^2=-12 are x=1-sqrt(5),x=1+sqrt(5)