What are the solutions to the equation 4x^2+9=0 ?

The solutions to the equation 4x^2+9=0 are x= 3/2 i,x=-3/2 i

Find the zeros of 4x^2+9=0

The zeros of 4x^2+9=0 are x= 3/2 i,x=-3/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 9 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

4 x^{2} + 9 = 0

Move

9

to the right side

4 x^{2} = - 9

Divide both sides by

4

x^{2} = - \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{9}{4}, x = - - \frac{9}{4}

- \frac{9}{4} = \frac{3}{2} i

- - \frac{9}{4} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

x^{3} > x^{2}

\frac{1}{4} (m + 8) > \frac{1}{2}

3 x^{3} - 12 x y + x^{2} y - 4 y^{2}

3 y^{2} + 20 y - 7

- 3 w^{2} + 19 w + 14

What are the solutions to the equation 4x^2+9=0 ?
The solutions to the equation 4x^2+9=0 are x= 3/2 i,x=-3/2 i
Find the zeros of 4x^2+9=0
The zeros of 4x^2+9=0 are x= 3/2 i,x=-3/2 i