What are the solutions to the equation 6x^2+17x+12=0 ?

The solutions to the equation 6x^2+17x+12=0 are x=-4/3 ,x=-3/2

Find the zeros of 6x^2+17x+12=0

The zeros of 6x^2+17x+12=0 are x=-4/3 ,x=-3/2

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6 x^{2} + 17 x + 12 = 0

x = - \frac{4}{3}, x = - \frac{3}{2}

Solution steps

6 x^{2} + 17 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 6 \cdot 12}{2 \cdot 6}

1 7^{2} - 4 \cdot 6 \cdot 12 = 1

x_{1, 2} = \frac{- 17 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 17 + 1}{2 \cdot 6}, x_{2} = \frac{- 17 - 1}{2 \cdot 6}

x = \frac{- 17 + 1}{2 \cdot 6} : - \frac{4}{3}

x = \frac{- 17 - 1}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = - \frac{3}{2}

2 x + 2 y + a x + a y

9 x^{2} - 4 y^{2}

5 y^{5} + 21 y^{6} - 6 y^{7}

7 = \frac{8}{5} (3 x + 5)

2 (3 u - 8) = 38

What are the solutions to the equation 6x^2+17x+12=0 ?
The solutions to the equation 6x^2+17x+12=0 are x=-4/3 ,x=-3/2
Find the zeros of 6x^2+17x+12=0
The zeros of 6x^2+17x+12=0 are x=-4/3 ,x=-3/2