What are the solutions to the equation x^2-x+10=0 ?

The solutions to the equation x^2-x+10=0 are x= 1/2+i(sqrt(39))/2 ,x= 1/2-i(sqrt(39))/2

Find the zeros of x^2-x+10=0

The zeros of x^2-x+10=0 are x= 1/2+i(sqrt(39))/2 ,x= 1/2-i(sqrt(39))/2

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x^{2} - x + 10 = 0

x = \frac{1}{2} + i \frac{39}{2}, x = \frac{1}{2} - i \frac{39}{2}

Solution steps

x^{2} - x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 10 : 39 i

x_{1, 2} = \frac{- ( - 1 ) \pm 39 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 39 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 39 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 39 i}{2 \cdot 1} : \frac{1}{2} + i \frac{39}{2}

x = \frac{- ( - 1 ) - 39 i}{2 \cdot 1} : \frac{1}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{39}{2}, x = \frac{1}{2} - i \frac{39}{2}

k + 6 > 19

- 6 x + 18 \leq 12

\frac{1}{1 + e ^{- 0.805}}

8 x^{2} - 23 x - 3

- \frac{1}{4} - \frac{3}{4}

What are the solutions to the equation x^2-x+10=0 ?
The solutions to the equation x^2-x+10=0 are x= 1/2+i(sqrt(39))/2 ,x= 1/2-i(sqrt(39))/2
Find the zeros of x^2-x+10=0
The zeros of x^2-x+10=0 are x= 1/2+i(sqrt(39))/2 ,x= 1/2-i(sqrt(39))/2