What is the answer to (x-5)^2+4=x^2-7x ?

The answer to (x-5)^2+4=x^2-7x is x= 29/3

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(x-5)^2+4=x^2-7x

(x - 5)^{2} + 4 = x^{2} - 7 x

x = \frac{29}{3}

Decimal Notation

x = 9.66666 \dots

Solution steps

(x - 5)^{2} + 4 = x^{2} - 7 x

Expand

(x - 5)^{2} + 4 : x^{2} - 10 x + 29

x^{2} - 10 x + 29 = x^{2} - 7 x

Move

29

to the right side

x^{2} - 10 x = x^{2} - 7 x - 29

Subtract

x^{2} - 7 x

from both sides

x^{2} - 10 x - (x^{2} - 7 x) = x^{2} - 7 x - 29 - (x^{2} - 7 x)

Simplify

- 3 x = - 29

Divide both sides by

- 3

x = \frac{29}{3}

x, 7 x 9 = (7 x 10) - (7 x y)

- 10 (- 6 x - 3) + 5 = 4 x - 7 (- 8 x - 5)

4 x = \frac{3}{2}

x, 4 x - 3 y - 6 = 0

4 x + 9 = 18 - \frac{1}{2} x

What is the answer to (x-5)^2+4=x^2-7x ?
The answer to (x-5)^2+4=x^2-7x is x= 29/3
Solve for x: (x-5)^2+4=x^2-7x
The solution is x= 29/3