What are the solutions to the equation 3x^2-16x-4=0 ?

The solutions to the equation 3x^2-16x-4=0 are x=(2(4+sqrt(19)))/3 ,x=(2(4-sqrt(19)))/3

Find the zeros of 3x^2-16x-4=0

The zeros of 3x^2-16x-4=0 are x=(2(4+sqrt(19)))/3 ,x=(2(4-sqrt(19)))/3

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3 x^{2} - 16 x - 4 = 0

x = \frac{2 ( 4 + 19 )}{3}, x = \frac{2 ( 4 - 19 )}{3}

Decimal Notation

x = 5.57259 \dots, x = - 0.23926 \dots

Solution steps

3 x^{2} - 16 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 4) = 419

x_{1, 2} = \frac{- ( - 16 ) \pm 4 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 19}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 4 19}{2 \cdot 3}

x = \frac{- ( - 16 ) + 4 19}{2 \cdot 3} : \frac{2 ( 4 + 19 )}{3}

x = \frac{- ( - 16 ) - 4 19}{2 \cdot 3} : \frac{2 ( 4 - 19 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 4 + 19 )}{3}, x = \frac{2 ( 4 - 19 )}{3}

12 x^{2} - 60 x + 44

3 x + 5 = 3 (x + 5)

2 (- n - 3) - 7 (5 + 2 n)

s^{4} + s^{3} - s^{2} - s

t^{2} = 11 t - 18

What are the solutions to the equation 3x^2-16x-4=0 ?
The solutions to the equation 3x^2-16x-4=0 are x=(2(4+sqrt(19)))/3 ,x=(2(4-sqrt(19)))/3
Find the zeros of 3x^2-16x-4=0
The zeros of 3x^2-16x-4=0 are x=(2(4+sqrt(19)))/3 ,x=(2(4-sqrt(19)))/3