What is the answer to 4(2r-17)+5(3r-8)=0 ?

The answer to 4(2r-17)+5(3r-8)=0 is r= 108/23

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4(2r-17)+5(3r-8)=0

4 (2 r - 17) + 5 (3 r - 8) = 0

r = \frac{108}{23}

Solution steps

4 (2 r - 17) + 5 (3 r - 8) = 0

Expand

4 (2 r - 17) + 5 (3 r - 8) : 23 r - 108

23 r - 108 = 0

Move

108

to the right side

23 r = 108

Divide both sides by

23

r = \frac{108}{23}

4 (3 d + 2) = 8 (2 d + 4)

2 - 3 x = 2

4 (2 - x) + 15 = 3 (x + 3)

x + \frac{x}{2} = 15

5 (4 x - 4) = 5 (3 x + 3)

What is the answer to 4(2r-17)+5(3r-8)=0 ?
The answer to 4(2r-17)+5(3r-8)=0 is r= 108/23
Solve for r: 4(2r-17)+5(3r-8)=0
The solution is r= 108/23