What are the solutions to the equation 4x^2+x-18=0 ?

The solutions to the equation 4x^2+x-18=0 are x=2,x=-9/4

Find the zeros of 4x^2+x-18=0

The zeros of 4x^2+x-18=0 are x=2,x=-9/4

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4 x^{2} + x - 18 = 0

x = 2, x = - \frac{9}{4}

Decimal Notation

x = 2, x = - 2.25

Solution steps

4 x^{2} + x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 18 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 18) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 4}, x_{2} = \frac{- 1 - 17}{2 \cdot 4}

x = \frac{- 1 + 17}{2 \cdot 4} : 2

x = \frac{- 1 - 17}{2 \cdot 4} : - \frac{9}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{9}{4}

0.4 (u e^{- 4})^{2} = 0.2 (\frac{u e ^{- 4} - u}{4})

x (b - 4) + z (b - 4)

\frac{52 !}{5 ! ( 52 - 5 ) !}

\frac{4}{3} \cdot π \cdot 3^{3}

\frac{3}{a} + \frac{7}{b}

What are the solutions to the equation 4x^2+x-18=0 ?
The solutions to the equation 4x^2+x-18=0 are x=2,x=-9/4
Find the zeros of 4x^2+x-18=0
The zeros of 4x^2+x-18=0 are x=2,x=-9/4