What are the solutions to the equation 7x^2-14x-13=8 ?

The solutions to the equation 7x^2-14x-13=8 are x=3,x=-1

Find the zeros of 7x^2-14x-13=8

The zeros of 7x^2-14x-13=8 are x=3,x=-1

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7 x^{2} - 14 x - 13 = 8

x = 3, x = - 1

Solution steps

7 x^{2} - 14 x - 13 = 8

Move

8

to the left side

7 x^{2} - 14 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 ( - 21 )}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 (- 21) = 28

x_{1, 2} = \frac{- ( - 14 ) \pm 28}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 28}{2 \cdot 7}, x_{2} = \frac{- ( - 14 ) - 28}{2 \cdot 7}

x = \frac{- ( - 14 ) + 28}{2 \cdot 7} : 3

x = \frac{- ( - 14 ) - 28}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

\frac{x ^{2} + x}{x ^{2} - 1} > 0

∣ 8 x + 7 ∣ = 4

x^{2} - 2 x - 35 \leq 0

\frac{\frac{1}{y} - \frac{1}{x}}{\frac{x}{y} - \frac{y}{x}}

s^{\frac{3}{4}} \cdot s^{\frac{13}{4}}

What are the solutions to the equation 7x^2-14x-13=8 ?
The solutions to the equation 7x^2-14x-13=8 are x=3,x=-1
Find the zeros of 7x^2-14x-13=8
The zeros of 7x^2-14x-13=8 are x=3,x=-1