What are the solutions to the equation x^2+6x-1=-7 ?

The solutions to the equation x^2+6x-1=-7 are x=-3+sqrt(3),x=-3-sqrt(3)

Find the zeros of x^2+6x-1=-7

The zeros of x^2+6x-1=-7 are x=-3+sqrt(3),x=-3-sqrt(3)

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x^{2} + 6 x - 1 = - 7

x = - 3 + 3, x = - 3 - 3

Solution steps

x^{2} + 6 x - 1 = - 7

Move

7

to the left side

x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 1}

x = \frac{- 6 + 2 3}{2 \cdot 1} : - 3 + 3

x = \frac{- 6 - 2 3}{2 \cdot 1} : - 3 - 3

The solutions to the quadratic equation are:

x = - 3 + 3, x = - 3 - 3

3 x - 5 < - 17 and - 6 x + 5 > 11

2 s^{2} - 11 s + 5

4 (x + 1) = 2 x + 2

\frac{z}{3} \leq 3

\frac{8 k ^{3}}{7 k + 2} + \frac{11}{3 k}

What are the solutions to the equation x^2+6x-1=-7 ?
The solutions to the equation x^2+6x-1=-7 are x=-3+sqrt(3),x=-3-sqrt(3)
Find the zeros of x^2+6x-1=-7
The zeros of x^2+6x-1=-7 are x=-3+sqrt(3),x=-3-sqrt(3)