What is the answer to i+5j-7kyB=4i-2j+8k,A=2 ?

The answer to i+5j-7kyB=4i-2j+8k,A=2 is y=(7j-8k)/(7kB)-i 3/(7kB);\quad k\ne 0

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i+5j-7kyB=4i-2j+8k,A=2

i + 5 j - 7 k y B = 4 i - 2 j + 8 k, A = 2

y = \frac{7 j - 8 k}{7 k B} - i \frac{3}{7 k B}; k \neq = 0

Solution steps

i + 5 j - 7 k y B = 4 i - 2 j + 8 k

Move

i

to the right side

5 j - 7 k y B = 3 i + 8 k - 2 j

Move

5 j

to the right side

- 7 k y B = 3 i + 8 k - 7 j

Divide both sides by

- 7 k B; k \neq = 0

y = \frac{7 j - 8 k}{7 k B} - i \frac{3}{7 k B}; k \neq = 0

\frac{n + 4}{2} = - 9

0.4 = 0.38 (u + 1) - 0.22 u

9 + 4 (x + 1) = 25

\frac{5}{7} (k + 5) = - 7

21 - (2 v + 17) = - 7 - 3 v

What is the answer to i+5j-7kyB=4i-2j+8k,A=2 ?
The answer to i+5j-7kyB=4i-2j+8k,A=2 is y=(7j-8k)/(7kB)-i 3/(7kB);\quad k\ne 0