What is the answer to 27+8x=a(x+4)+b(2x+3) ?

The answer to 27+8x=a(x+4)+b(2x+3) is x=(4a+3b-27)/(8-a-2b);\quad a\ne-2b+8

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27+8x=a(x+4)+b(2x+3)

27 + 8 x = a (x + 4) + b (2 x + 3)

x = \frac{4 a + 3 b - 27}{8 - a - 2 b}; a \neq = - 2 b + 8

Solution steps

27 + 8 x = a (x + 4) + b (2 x + 3)

Expand

a (x + 4) : a x + 4 a

27 + 8 x = a x + 4 a + b (2 x + 3)

Expand

b (2 x + 3) : 2 b x + 3 b

27 + 8 x = a x + 4 a + 2 b x + 3 b

Move

27

to the right side

8 x = a x + 4 a + 2 b x + 3 b - 27

Subtract

a x + 2 b x

from both sides

8 x - (a x + 2 b x) = a x + 4 a + 2 b x + 3 b - 27 - (a x + 2 b x)

Simplify

8 x - a x - 2 b x = 4 a + 3 b - 27

Factor

8 x - a x - 2 b x : x (8 - a - 2 b)

x (8 - a - 2 b) = 4 a + 3 b - 27

Divide both sides by

8 - a - 2 b; a \neq = - 2 b + 8

x = \frac{4 a + 3 b - 27}{8 - a - 2 b}; a \neq = - 2 b + 8

5 z - 11 = - 8

x, f = 0.3 x - 1

5 (x - 7) = 2 (x + 14)

1 = 0.2 x - 0.6 x - 3

- 3 (2 - x) = 2 x

What is the answer to 27+8x=a(x+4)+b(2x+3) ?
The answer to 27+8x=a(x+4)+b(2x+3) is x=(4a+3b-27)/(8-a-2b);\quad a\ne-2b+8