What are the solutions to the equation x(x+8)=256 ?

The solutions to the equation x(x+8)=256 are x=4(sqrt(17)-1),x=-4(1+sqrt(17))

Find the zeros of x(x+8)=256

The zeros of x(x+8)=256 are x=4(sqrt(17)-1),x=-4(1+sqrt(17))

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x (x + 8) = 256

x = 4 (17 - 1), x = - 4 (1 + 17)

Solution steps

x (x + 8) = 256

Expand

x (x + 8) : x^{2} + 8 x

x^{2} + 8 x = 256

Move

256

to the left side

x^{2} + 8 x - 256 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 256 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 256) = 817

x_{1, 2} = \frac{- 8 \pm 8 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 17}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 17}{2 \cdot 1}

x = \frac{- 8 + 8 17}{2 \cdot 1} : 4 (17 - 1)

x = \frac{- 8 - 8 17}{2 \cdot 1} : - 4 (1 + 17)

The solutions to the quadratic equation are:

x = 4 (17 - 1), x = - 4 (1 + 17)

lo g_{7} (5764801) = x

x \cdot x + h

∣ x - 2 ∣ \leq 8

\frac{5}{n + 1} \cdot \frac{n + 1}{n + 3}

x^{2} + 6^{2} = 1 0^{2}

What are the solutions to the equation x(x+8)=256 ?
The solutions to the equation x(x+8)=256 are x=4(sqrt(17)-1),x=-4(1+sqrt(17))
Find the zeros of x(x+8)=256
The zeros of x(x+8)=256 are x=4(sqrt(17)-1),x=-4(1+sqrt(17))