What is the answer to 3(2-x)+4x=6-[3-(2-2x)] ?

The answer to 3(2-x)+4x=6-[3-(2-2x)] is x=-1/3

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3(2-x)+4x=6-[3-(2-2x)]

3 (2 - x) + 4 x = 6 - [3 - (2 - 2 x)]

x = - \frac{1}{3}

Solution steps

3 (2 - x) + 4 x = 6 - [3 - (2 - 2 x)]

Expand

3 (2 - x) : 6 - 3 x

6 - 3 x + 4 x = 6 - [3 - (2 - 2 x)]

Add similar elements:

- 3 x + 4 x = x

6 + x = 6 - [3 - (2 - 2 x)]

Expand

6 - (3 - (2 - 2 x)) : - 2 x + 5

6 + x = - 2 x + 5

Move

6

to the right side

x = - 2 x - 1

Move

2 x

to the left side

3 x = - 1

Divide both sides by

3

x = - \frac{1}{3}

M = \frac{( 1 + i ) ^{1} 1}{( 32 ( 1 - i ) )}

c, 3 c + 4 d = 5

a^{2} x + (a - 5) = (a + 5) x

x + (- 4) = 9

- 8 m + 14 = 2 m - 16

What is the answer to 3(2-x)+4x=6-[3-(2-2x)] ?
The answer to 3(2-x)+4x=6-[3-(2-2x)] is x=-1/3
Solve for x: 3(2-x)+4x=6-[3-(2-2x)]
The solution is x=-1/3