What is the answer to 2x(3x+1)=2x(3x-1) ?

The answer to 2x(3x+1)=2x(3x-1) is x=0

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2x(3x+1)=2x(3x-1)

2 x (3 x + 1) = 2 x (3 x - 1)

x = 0

Solution steps

2 x (3 x + 1) = 2 x (3 x - 1)

Expand

2 x (3 x + 1) : 6 x^{2} + 2 x

Expand

2 x (3 x - 1) : 6 x^{2} - 2 x

6 x^{2} + 2 x = 6 x^{2} - 2 x

Subtract

6 x^{2} - 2 x

from both sides

6 x^{2} + 2 x - (6 x^{2} - 2 x) = 6 x^{2} - 2 x - (6 x^{2} - 2 x)

Simplify

4 x = 0

Divide both sides by

4

x = 0

4 - (x - 1) = - 6 + \frac{3}{2} (- 4 x + 4)

3 x - 2 = 4 x + 1

x, 5 x + 7 y = 2

4 - x - 10 = 8 x - 12 - 4 x

4 (6 + y) = 9 - 5 + 8 y

What is the answer to 2x(3x+1)=2x(3x-1) ?
The answer to 2x(3x+1)=2x(3x-1) is x=0
Solve for x: 2x(3x+1)=2x(3x-1)
The solution is x=0