What is the answer to m^3-1=(m-1)(1+m+m^2) ?

The answer to m^3-1=(m-1)(1+m+m^2) is True for all m

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m^3-1=(m-1)(1+m+m^2)

m^{3} - 1 = (m - 1) (1 + m + m^{2})

True for all m

Solution steps

m^{3} - 1 = (m - 1) (1 + m + m^{2})

Expand

(m - 1) (1 + m + m^{2}) : m^{3} - 1

m^{3} - 1 = m^{3} - 1

Move

1

to the right side

m^{3} = m^{3}

Move

m^{3}

to the left side

0 = 0

Both sides are equal

True for all m

4 + \frac{1}{5} r = - 1

8 (6 x - 6) - 28 = - 28

f = (0 + 7)^{2} + 1

20 = 3 x - 5 (- 4)

7 x - 1 = 9 x + 5

What is the answer to m^3-1=(m-1)(1+m+m^2) ?
The answer to m^3-1=(m-1)(1+m+m^2) is True for all m
Solve for m: m^3-1=(m-1)(1+m+m^2)
The solution is True for all m