What are the solutions to the equation 9x^2+1=6x ?

The solutions to the equation 9x^2+1=6x are x= 1/3

Find the zeros of 9x^2+1=6x

The zeros of 9x^2+1=6x are x= 1/3

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9 x^{2} + 1 = 6 x

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

9 x^{2} + 1 = 6 x

Move

6 x

to the left side

9 x^{2} + 1 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

lo g_{27} (3)

8 a^{2} - 4 = - 5

\frac{( x - 4 )}{5 x + 7} \leq 2

125 q^{3} - w^{3}

What are the solutions to the equation 9x^2+1=6x ?
The solutions to the equation 9x^2+1=6x are x= 1/3
Find the zeros of 9x^2+1=6x
The zeros of 9x^2+1=6x are x= 1/3