What is the answer to solvefor x,y(3-2x-3y)=0 ?

The answer to solvefor x,y(3-2x-3y)=0 is x=-(3y-3)/2

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solvefor x,y(3-2x-3y)=0

solve for

x, y (3 - 2 x - 3 y) = 0

x = - \frac{3 y - 3}{2}

Solution steps

y (3 - 2 x - 3 y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 - 2 x - 3 y = 0

Move

3 y

to the right side

3 - 2 x = 3 y

Move

3

to the right side

- 2 x = 3 y - 3

Divide both sides by

- 2

x = - \frac{3 y - 3}{2}

k, g^{- 1} (k + 1) = 2 k

28 - \frac{x}{3} = \frac{x}{4}

\frac{j}{9} = 5

11 b - 6 = - 28

3 x - 10 = 2

What is the answer to solvefor x,y(3-2x-3y)=0 ?
The answer to solvefor x,y(3-2x-3y)=0 is x=-(3y-3)/2