What is ((3abc)^3)/((2a^{-1)b^{-2}c)^2} ?

The solution to ((3abc)^3)/((2a^{-1)b^{-2}c)^2} is (27a^5b^7c)/4

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simplify ((3abc)^3)/((2a^{-1)b^{-2}c)^2}

simplify

\frac{( 3 ab c ) ^{3}}{( 2 a ^{- 1} b ^{- 2} c ) ^{2}}

\frac{27 a ^{5} b ^{7} c}{4}

Solution steps

\frac{( 3 ab c ) ^{3}}{( 2 a ^{- 1} b ^{- 2} c ) ^{2}}

Simplify

(3 ab c)^{3} : 27 a^{3} b^{3} c^{3}

= \frac{27 a ^{3} b ^{3} c ^{3}}{( 2 a ^{- 1} b ^{- 2} c ) ^{2}}

Simplify

(2 a^{- 1} b^{- 2} c)^{2} : \frac{4 c ^{2}}{a ^{2} b ^{4}}

= \frac{27 a ^{3} b ^{3} c ^{3}}{\frac{4 c ^{2}}{a ^{2} b ^{4}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{27 a ^{3} b ^{3} c ^{3} a ^{2} b ^{4}}{4 c ^{2}}

Cancel

\frac{27 a ^{3} b ^{3} c ^{3} a ^{2} b ^{4}}{4 c ^{2}} : \frac{27 a ^{5} b ^{7} c}{4}

= \frac{27 a ^{5} b ^{7} c}{4}

3 w^{2} - 21 w = 0

x^{2} - 29 x + 198

171

∣ 3 x ∣ = - 9

- 14 x^{8} y + 12 x y^{9}

What is ((3abc)^3)/((2a^{-1)b^{-2}c)^2} ?
The solution to ((3abc)^3)/((2a^{-1)b^{-2}c)^2} is (27a^5b^7c)/4