What is the answer to (2x}{x+1}=\frac{2x-1)/x ?

The answer to (2x}{x+1}=\frac{2x-1)/x is x=1

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(2x}{x+1}=\frac{2x-1)/x

\frac{2 x}{x + 1} = \frac{2 x - 1}{x}

x = 1

Solution steps

\frac{2 x}{x + 1} = \frac{2 x - 1}{x}

Cross multiply

2 x^{2} = 2 x^{2} + x - 1

Subtract

2 x^{2} + x

from both sides

2 x^{2} - (2 x^{2} + x) = 2 x^{2} + x - 1 - (2 x^{2} + x)

Simplify

- x = - 1

Divide both sides by

- 1

x = 1

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Combine undefined points with solutions:

x = 1

\frac{5 x + 6}{3 x - 9} = \frac{7}{3}

\frac{1}{x} = \frac{4}{3 x} + 1

\frac{1}{x - 2} + \frac{x}{3} = 2

\frac{2}{x} = \frac{x}{32}

\frac{1}{2 x - 1} - \frac{1}{x} = 0

What is the answer to (2x}{x+1}=\frac{2x-1)/x ?
The answer to (2x}{x+1}=\frac{2x-1)/x is x=1
Solve for x: (2x}{x+1}=\frac{2x-1)/x
The solution is x=1