What is the answer to 1/x-1/(x+2)=2 ?

The answer to 1/x-1/(x+2)=2 is x=-1+sqrt(2),x=-1-sqrt(2)

Solve for x: 1/x-1/(x+2)=2

The solution is x=-1+sqrt(2),x=-1-sqrt(2)

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\frac{1}{x} - \frac{1}{x + 2} = 2

x = - 1 + 2, x = - 1 - 2

Decimal Notation

x = 0.41421 \dots, x = - 2.41421 \dots

Solution steps

\frac{1}{x} - \frac{1}{x + 2} = 2

Multiply by LCM

2 = 2 x (x + 2)

Solve

2 = 2 x (x + 2) : x = - 1 + 2, x = - 1 - 2

x = - 1 + 2, x = - 1 - 2

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 2

Combine undefined points with solutions:

x = - 1 + 2, x = - 1 - 2

\frac{4}{x - 3} = \frac{5}{x - 2}

\frac{x ^{2}}{x + 100} = 50

\frac{x - 2}{x - 1} = \frac{4}{x + 2}

\frac{10}{5 x - 9} = \frac{8}{2 x - 8}

\frac{5}{3} = \frac{2}{x + 4}

What is the answer to 1/x-1/(x+2)=2 ?
The answer to 1/x-1/(x+2)=2 is x=-1+sqrt(2),x=-1-sqrt(2)
Solve for x: 1/x-1/(x+2)=2
The solution is x=-1+sqrt(2),x=-1-sqrt(2)