What is the answer to (x+1)(1+1/(x-3))x=0 ?

The answer to (x+1)(1+1/(x-3))x=0 is x=0,x=-1,x=2

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(x+1)(1+1/(x-3))x=0

(x + 1) (1 + \frac{1}{x - 3}) x = 0

x = 0, x = - 1, x = 2

Solution steps

(x + 1) (1 + \frac{1}{x - 3}) x = 0

Expand

(x + 1) (1 + \frac{1}{x - 3}) x : \frac{x ^{3} - x ^{2} - 2 x}{x - 3}

\frac{x ^{3} - x ^{2} - 2 x}{x - 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{3} - x^{2} - 2 x = 0

Solve

x^{3} - x^{2} - 2 x = 0 : x = 0, x = - 1, x = 2

x = 0, x = - 1, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 3

Combine undefined points with solutions:

x = 0, x = - 1, x = 2

\frac{4}{n + 9} = \frac{2}{7}

\frac{3}{x} + \frac{5}{x + 2} = 2

x + \frac{6}{x} = 5

y, x = \frac{1}{y}

\frac{4}{x - 3} = 0

What is the answer to (x+1)(1+1/(x-3))x=0 ?
The answer to (x+1)(1+1/(x-3))x=0 is x=0,x=-1,x=2
Solve for x: (x+1)(1+1/(x-3))x=0
The solution is x=0,x=-1,x=2