What is the answer to (3x-1)^{-1}=2x^{-1} ?

The answer to (3x-1)^{-1}=2x^{-1} is x= 2/5

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(3x-1)^{-1}=2x^{-1}

(3 x - 1)^{- 1} = 2 x^{- 1}

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

(3 x - 1)^{- 1} = 2 x^{- 1}

Refine

\frac{1}{3 x - 1} = \frac{2}{x}

Cross multiply

x = 6 x - 2

Move

6 x

to the left side

- 5 x = - 2

Divide both sides by

- 5

x = \frac{2}{5}

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{3}, x = 0

Combine undefined points with solutions:

x = \frac{2}{5}

2 + \frac{2}{x} = 3

\frac{6}{x + 6} = \frac{5}{x + 5}

\frac{6}{b - 1} = \frac{9}{7}

10 - \frac{13}{x} = 4 + \frac{5}{x}

(x + 1)^{- 1} = x^{- 1} + x

What is the answer to (3x-1)^{-1}=2x^{-1} ?
The answer to (3x-1)^{-1}=2x^{-1} is x= 2/5
Solve for x: (3x-1)^{-1}=2x^{-1}
The solution is x= 2/5