What is the answer to (x^2+x-6)/(x-2)=x+3 ?

The answer to (x^2+x-6)/(x-2)=x+3 is x\ne 2

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(x^2+x-6)/(x-2)=x+3

\frac{x ^{2} + x - 6}{x - 2} = x + 3

x \neq = 2

Solution steps

\frac{x ^{2} + x - 6}{x - 2} = x + 3

Simplify

\frac{x ^{2} + x - 6}{x - 2} : x + 3

x + 3 = x + 3

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 2

Since the equation is undefined for:

2

x \neq = 2

\frac{2}{x - 2} = 2

a = \frac{1}{2 h ( b ^{1} + b ^{2} )}

x = 1 + \frac{1}{x}

\frac{x - 1}{x - 2} = \frac{1}{2}

\frac{7}{x + 9} = \frac{21}{36}

What is the answer to (x^2+x-6)/(x-2)=x+3 ?
The answer to (x^2+x-6)/(x-2)=x+3 is x\ne 2
Solve for x: (x^2+x-6)/(x-2)=x+3
The solution is x\ne 2