What is the answer to (x^2-1)/(x-1)=x+1 ?

The answer to (x^2-1)/(x-1)=x+1 is x\ne 1

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(x^2-1)/(x-1)=x+1

\frac{x ^{2} - 1}{x - 1} = x + 1

x \neq = 1

Solution steps

\frac{x ^{2} - 1}{x - 1} = x + 1

Simplify

\frac{x ^{2} - 1}{x - 1} : x + 1

x + 1 = x + 1

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 1

Since the equation is undefined for:

1

x \neq = 1

B, 2 = \frac{a}{2 B + q}

\frac{x - 3}{x} = \frac{9}{10}

y, x = \frac{2 y}{y - 1}

\frac{7}{9} = \frac{x + 3}{4 - x}

\frac{x}{2} + \frac{12}{x} = 5

What is the answer to (x^2-1)/(x-1)=x+1 ?
The answer to (x^2-1)/(x-1)=x+1 is x\ne 1
Solve for x: (x^2-1)/(x-1)=x+1
The solution is x\ne 1