What is the answer to (3x}{2x-1}=\frac{2x+1)/x ?

The answer to (3x}{2x-1}=\frac{2x+1)/x is x=1,x=-1

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(3x}{2x-1}=\frac{2x+1)/x

\frac{3 x}{2 x - 1} = \frac{2 x + 1}{x}

x = 1, x = - 1

Solution steps

\frac{3 x}{2 x - 1} = \frac{2 x + 1}{x}

Cross multiply

3 x^{2} = (2 x - 1) (2 x + 1)

Solve

3 x^{2} = (2 x - 1) (2 x + 1) : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{2}, x = 0

Combine undefined points with solutions:

x = 1, x = - 1

0.2 = \frac{x ^{2}}{35 - x}

\frac{4 r}{5 r + 6} = \frac{1}{6}

x^{- 2} = \frac{1}{4}

\frac{3}{x + 1} = \frac{2}{x + 4}

\frac{x}{4 - x} = 3 - x

What is the answer to (3x}{2x-1}=\frac{2x+1)/x ?
The answer to (3x}{2x-1}=\frac{2x+1)/x is x=1,x=-1
Solve for x: (3x}{2x-1}=\frac{2x+1)/x
The solution is x=1,x=-1