What is the answer to (3x+5)/((x-1)(x^4+7))=0 ?

The answer to (3x+5)/((x-1)(x^4+7))=0 is x=-5/3

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(3x+5)/((x-1)(x^4+7))=0

\frac{3 x + 5}{( x - 1 ) ( x ^{4} + 7 )} = 0

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

\frac{3 x + 5}{( x - 1 ) ( x ^{4} + 7 )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x + 5 = 0

Move

5

to the right side

3 x = - 5

Divide both sides by

3

x = - \frac{5}{3}

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = - \frac{5}{3}

\frac{p + 2}{p + 7} = \frac{3}{6}

\frac{2}{g + 6} = \frac{4}{5 g + 10}

\frac{4}{3} = \frac{11}{k}

2 x - 0.2 x^{2} = \frac{1}{2 x}

\frac{x - 7}{2 x - 9} = \frac{4}{3}

What is the answer to (3x+5)/((x-1)(x^4+7))=0 ?
The answer to (3x+5)/((x-1)(x^4+7))=0 is x=-5/3
Solve for x: (3x+5)/((x-1)(x^4+7))=0
The solution is x=-5/3