What is the answer to (x^2-4)/(x+3)=0 ?

The answer to (x^2-4)/(x+3)=0 is x=2,x=-2

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(x^2-4)/(x+3)=0

\frac{x ^{2} - 4}{x + 3} = 0

x = 2, x = - 2

Solution steps

\frac{x ^{2} - 4}{x + 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 4 = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = - 3

Combine undefined points with solutions:

x = 2, x = - 2

\frac{1}{x + 1} = 0

\frac{x - 5}{x + 4} = \frac{7}{6}

\frac{4 x - 1}{3 x - 7} = \frac{7}{4}

\frac{x + 1}{x - 1} = \frac{3}{2}

4 - \frac{5}{3 x - 7} = 4

What is the answer to (x^2-4)/(x+3)=0 ?
The answer to (x^2-4)/(x+3)=0 is x=2,x=-2
Solve for x: (x^2-4)/(x+3)=0
The solution is x=2,x=-2