What is the answer to x-2-(x^2-3x+2)/(x-1)=0 ?

The answer to x-2-(x^2-3x+2)/(x-1)=0 is x\ne 1

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x-2-(x^2-3x+2)/(x-1)=0

x - 2 - \frac{x ^{2} - 3 x + 2}{x - 1} = 0

x \neq = 1

Solution steps

x - 2 - \frac{x ^{2} - 3 x + 2}{x - 1} = 0

Simplify

- \frac{x ^{2} - 3 x + 2}{x - 1} : - x + 2

x - 2 - x + 2 = 0

Solve

x - 2 - x + 2 = 0 :

True for all

x

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 1

Since the equation is undefined for:

1

x \neq = 1

0.2 = \frac{x ^{2}}{15 - x}

\frac{w - 2}{w} = \frac{3}{6}

\frac{x - 6}{x} = \frac{x + 4}{x} + 1

\frac{1}{x} = 1

4 = \frac{2}{3 x + 2}

What is the answer to x-2-(x^2-3x+2)/(x-1)=0 ?
The answer to x-2-(x^2-3x+2)/(x-1)=0 is x\ne 1
Solve for x: x-2-(x^2-3x+2)/(x-1)=0
The solution is x\ne 1