What are the solutions to the equation 8n^2+7n-15=-7 ?

The solutions to the equation 8n^2+7n-15=-7 are n=(-7+sqrt(305))/(16),n=(-7-sqrt(305))/(16)

Find the zeros of 8n^2+7n-15=-7

The zeros of 8n^2+7n-15=-7 are n=(-7+sqrt(305))/(16),n=(-7-sqrt(305))/(16)

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8 n^{2} + 7 n - 15 = - 7

n = \frac{- 7 + 305}{16}, n = \frac{- 7 - 305}{16}

Solution steps

8 n^{2} + 7 n - 15 = - 7

Move

7

to the left side

8 n^{2} + 7 n - 8 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 8 ( - 8 )}{2 \cdot 8}

7^{2} - 4 \cdot 8 (- 8) = 305

n_{1, 2} = \frac{- 7 \pm 305}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- 7 + 305}{2 \cdot 8}, n_{2} = \frac{- 7 - 305}{2 \cdot 8}

n = \frac{- 7 + 305}{2 \cdot 8} : \frac{- 7 + 305}{16}

n = \frac{- 7 - 305}{2 \cdot 8} : \frac{- 7 - 305}{16}

The solutions to the quadratic equation are:

n = \frac{- 7 + 305}{16}, n = \frac{- 7 - 305}{16}

- 1 - 5

x^{2} + 4 (\frac{- 1 - x}{2})^{2} = 25

2 \leq 3 y + 11 \leq 14

3 m \geq 9

2 x^{2} - 8 x - 14 = 0

What are the solutions to the equation 8n^2+7n-15=-7 ?
The solutions to the equation 8n^2+7n-15=-7 are n=(-7+sqrt(305))/(16),n=(-7-sqrt(305))/(16)
Find the zeros of 8n^2+7n-15=-7
The zeros of 8n^2+7n-15=-7 are n=(-7+sqrt(305))/(16),n=(-7-sqrt(305))/(16)