What is the answer to solvefor x,y=(x^2+3)/x ?

The answer to solvefor x,y=(x^2+3)/x is x=(y+sqrt(y^2-12))/2 ,x=(y-sqrt(y^2-12))/2

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solvefor x,y=(x^2+3)/x

solve for

x, y = \frac{x ^{2} + 3}{x}

x = \frac{y + y ^{2} - 12}{2}, x = \frac{y - y ^{2} - 12}{2}

Solution steps

y = \frac{x ^{2} + 3}{x}

Multiply both sides by

x

y x = x^{2} + 3

Solve

y x = x^{2} + 3 : x = \frac{y + y ^{2} - 12}{2}, x = \frac{y - y ^{2} - 12}{2}

x = \frac{y + y ^{2} - 12}{2}, x = \frac{y - y ^{2} - 12}{2}

0 = \frac{x ^{2} - x - 20}{x + 6}

\frac{3}{20 - 2 x} - 1 = \frac{x}{18}

\frac{x}{2 x - 3} + \frac{4}{x + 1} = 1

b, \frac{a}{b} = c

\frac{x - 7}{x + 2} = \frac{7}{4}

What is the answer to solvefor x,y=(x^2+3)/x ?
The answer to solvefor x,y=(x^2+3)/x is x=(y+sqrt(y^2-12))/2 ,x=(y-sqrt(y^2-12))/2