What is the answer to 1=(2x^2)/(x^4+1) ?

The answer to 1=(2x^2)/(x^4+1) is x=1,x=-1

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1=(2x^2)/(x^4+1)

1 = \frac{2 x ^{2}}{x ^{4} + 1}

x = 1, x = - 1

Solution steps

1 = \frac{2 x ^{2}}{x ^{4} + 1}

Multiply both sides by

x^{4} + 1

x^{4} + 1 = 2 x^{2}

Solve

x^{4} + 1 = 2 x^{2} : x = 1, x = - 1

x = 1, x = - 1

\frac{21}{x} = \frac{14}{4}

w, n = \frac{g}{w}

r, S = \frac{a}{1 - r}

\frac{3}{11} = \frac{6}{y}

y, x = \frac{y}{y + 2}

What is the answer to 1=(2x^2)/(x^4+1) ?
The answer to 1=(2x^2)/(x^4+1) is x=1,x=-1
Solve for x: 1=(2x^2)/(x^4+1)
The solution is x=1,x=-1