What is the answer to (x^2-9)/(x-3)=x^2-4x+9 ?

The answer to (x^2-9)/(x-3)=x^2-4x+9 is x=2

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(x^2-9)/(x-3)=x^2-4x+9

\frac{x ^{2} - 9}{x - 3} = x^{2} - 4 x + 9

x = 2

Solution steps

\frac{x ^{2} - 9}{x - 3} = x^{2} - 4 x + 9

Simplify

\frac{x ^{2} - 9}{x - 3} : x + 3

x + 3 = x^{2} - 4 x + 9

Solve

x + 3 = x^{2} - 4 x + 9 : x = 3, x = 2

x = 3, x = 2

Verify Solutions

Find undefined (singularity) points:

x = 3

Since the equation is undefined for:

3

x = 2

\frac{x - 5}{x - 7} = \frac{4}{3}

\frac{5}{x} - \frac{1}{x + 2} = 1

\frac{5 x - 5}{x + 1} = 3

\frac{3}{x} = \frac{21}{8 x} + 3

\frac{1}{2 x - 5} = \frac{x - 2}{x - 1}

What is the answer to (x^2-9)/(x-3)=x^2-4x+9 ?
The answer to (x^2-9)/(x-3)=x^2-4x+9 is x=2
Solve for x: (x^2-9)/(x-3)=x^2-4x+9
The solution is x=2