What is the answer to 1/(x+2)+1/(x+3)=1 ?

The answer to 1/(x+2)+1/(x+3)=1 is x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

Solve for x: 1/(x+2)+1/(x+3)=1

The solution is x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2

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\frac{1}{x + 2} + \frac{1}{x + 3} = 1

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

Decimal Notation

x = - 0.38196 \dots, x = - 2.61803 \dots

Solution steps

\frac{1}{x + 2} + \frac{1}{x + 3} = 1

Multiply by LCM

2 x + 5 = (x + 2) (x + 3)

Solve

2 x + 5 = (x + 2) (x + 3) : x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 2, x = - 3

Combine undefined points with solutions:

x = \frac{- 3 + 5}{2}, x = \frac{- 3 - 5}{2}

x, z = \frac{x y}{x + y}

\frac{2 x}{x + 4} = \frac{2 x - 4}{x}

\frac{x + 5}{2 x} = \frac{3}{4}

\frac{c + 2}{c - 2} = \frac{4}{8}

\frac{2 x}{x + 5} = \frac{2 x - 5}{x}

What is the answer to 1/(x+2)+1/(x+3)=1 ?
The answer to 1/(x+2)+1/(x+3)=1 is x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2
Solve for x: 1/(x+2)+1/(x+3)=1
The solution is x=(-3+sqrt(5))/2 ,x=(-3-sqrt(5))/2