What is the answer to (3x^2+5-3x)/(2x-1)=5x ?

The answer to (3x^2+5-3x)/(2x-1)=5x is x=-5/7 ,x=1

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(3x^2+5-3x)/(2x-1)=5x

\frac{3 x ^{2} + 5 - 3 x}{2 x - 1} = 5 x

x = - \frac{5}{7}, x = 1

Decimal Notation

x = - 0.71428 \dots, x = 1

Solution steps

\frac{3 x ^{2} + 5 - 3 x}{2 x - 1} = 5 x

Multiply both sides by

2 x - 1

3 x^{2} + 5 - 3 x = 5 x (2 x - 1)

Solve

3 x^{2} + 5 - 3 x = 5 x (2 x - 1) : x = - \frac{5}{7}, x = 1

x = - \frac{5}{7}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = \frac{1}{2}

Combine undefined points with solutions:

x = - \frac{5}{7}, x = 1

x, M = \frac{6 y - 1}{4 x + 5}

\frac{x - 8}{x - 5} = \frac{7}{8}

\frac{5 x - 3}{x} = \frac{7 - x}{x + 2}

\frac{x}{x - 1} - \frac{x}{x + 1} = 1

\frac{3 x + 3}{x - 3} = 5

What is the answer to (3x^2+5-3x)/(2x-1)=5x ?
The answer to (3x^2+5-3x)/(2x-1)=5x is x=-5/7 ,x=1
Solve for x: (3x^2+5-3x)/(2x-1)=5x
The solution is x=-5/7 ,x=1