What is the answer to (4x^3-9x)/(x+1.5)=0 ?

The answer to (4x^3-9x)/(x+1.5)=0 is x=0,x=-3/2 ,x= 3/2

Solve for x: (4x^3-9x)/(x+1.5)=0

The solution is x=0,x=-3/2 ,x= 3/2

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\frac{4 x ^{3} - 9 x}{x + 1.5} = 0

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5, x = 1.5

Solution steps

\frac{4 x ^{3} - 9 x}{x + 1.5} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 x^{3} - 9 x = 0

Solve

4 x^{3} - 9 x = 0 : x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 1.5

Combine undefined points with solutions:

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

\frac{\frac{1}{3} x - 5}{3 x + 4} = 2

\frac{2}{x + 4} = \frac{9}{x + 3}

\frac{6 - 2 x}{1 + x} = 2

\frac{2 x}{x ^{2} + 1} = 0

\frac{x}{x - 3} = \frac{2 x}{2}

What is the answer to (4x^3-9x)/(x+1.5)=0 ?
The answer to (4x^3-9x)/(x+1.5)=0 is x=0,x=-3/2 ,x= 3/2
Solve for x: (4x^3-9x)/(x+1.5)=0
The solution is x=0,x=-3/2 ,x= 3/2