What is the answer to solvefor y,x=(2y+3)/(y-1) ?

The answer to solvefor y,x=(2y+3)/(y-1) is y=(3+x)/(x-2);\quad x\ne 2

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solvefor y,x=(2y+3)/(y-1)

solve for

y, x = \frac{2 y + 3}{y - 1}

y = \frac{3 + x}{x - 2}; x \neq = 2

Solution steps

x = \frac{2 y + 3}{y - 1}

Multiply both sides by

y - 1

x (y - 1) = 2 y + 3

Expand

x (y - 1) : y x - x

y x - x = 2 y + 3

Move

x

to the right side

y x = 2 y + 3 + x

Move

2 y

to the left side

y x - 2 y = 3 + x

Factor

y x - 2 y : y (x - 2)

y (x - 2) = 3 + x

Divide both sides by

x - 2; x \neq = 2

y = \frac{3 + x}{x - 2}; x \neq = 2

\frac{x}{3} + \frac{12}{x} = x - 2

\frac{6}{2 x + 11} + 5 = 5

\frac{2 x - 3}{x + 4} = - 3

x, 4 y = \frac{3 x}{x + 1}

y, x = \frac{1}{y ^{2}}

What is the answer to solvefor y,x=(2y+3)/(y-1) ?
The answer to solvefor y,x=(2y+3)/(y-1) is y=(3+x)/(x-2);\quad x\ne 2