What is the answer to 36x^{-4}-13x^{-2}+1=0 ?

The answer to 36x^{-4}-13x^{-2}+1=0 is x=3,x=-3,x=2,x=-2

Solve for x: 36x^{-4}-13x^{-2}+1=0

The solution is x=3,x=-3,x=2,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

36 x^{- 4} - 13 x^{- 2} + 1 = 0

x = 3, x = - 3, x = 2, x = - 2

Solution steps

36 x^{- 4} - 13 x^{- 2} + 1 = 0

Refine

\frac{36}{x ^{4}} - \frac{13}{x ^{2}} + 1 = 0

Multiply by LCM

36 - 13 x^{2} + x^{4} = 0

Solve

36 - 13 x^{2} + x^{4} = 0 : x = 3, x = - 3, x = 2, x = - 2

x = 3, x = - 3, x = 2, x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 3, x = - 3, x = 2, x = - 2

\frac{4}{y} - 5 = \frac{18}{2 y}

\frac{4 x + 1}{x - 1} = \frac{3}{2}

x - \frac{7}{x} = 6

\frac{1}{x} = 13

\frac{1}{x} = x + 1

What is the answer to 36x^{-4}-13x^{-2}+1=0 ?
The answer to 36x^{-4}-13x^{-2}+1=0 is x=3,x=-3,x=2,x=-2
Solve for x: 36x^{-4}-13x^{-2}+1=0
The solution is x=3,x=-3,x=2,x=-2