What is (16a^4+16a)/(a^2+1-a) ?

The solution to (16a^4+16a)/(a^2+1-a) is 16a(a+1)

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simplify (16a^4+16a)/(a^2+1-a)

simplify

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

16 a (a + 1)

Solution steps

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

Factor

16 a^{4} + 16 a : 16 a (a^{3} + 1)

= \frac{16 a ( a ^{3} + 1 )}{a ^{2} + 1 - a}

Factor

a^{3} + 1 : (a + 1) (a^{2} - a + 1)

= \frac{16 a ( a + 1 ) ( a ^{2} - a + 1 )}{a ^{2} + 1 - a}

Apply the commutative law:

a^{2} + 1 - a = a^{2} - a + 1

= \frac{16 a ( a + 1 ) ( a ^{2} - a + 1 )}{a ^{2} - a + 1}

Cancel the common factor:

a^{2} - a + 1

= 16 a (a + 1)

(\frac{109}{50}) (\frac{157}{100})

\frac{64}{4}

k^{4} + 8 k^{3} + 16 k^{2}

3 a^{2} + 16 a + 5

- \frac{4}{7} - \frac{1}{4}

What is (16a^4+16a)/(a^2+1-a) ?
The solution to (16a^4+16a)/(a^2+1-a) is 16a(a+1)