What are the solutions to the equation (3y+9)^2=81 ?

The solutions to the equation (3y+9)^2=81 are y=0,y=-6

Find the zeros of (3y+9)^2=81

The zeros of (3y+9)^2=81 are y=0,y=-6

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(3 y + 9)^{2} = 81

y = 0, y = - 6

Solution steps

(3 y + 9)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 y + 9 = 81 : y = 0

Solve

3 y + 9 = - 81 : y = - 6

The solutions to the quadratic equation are:

y = 0, y = - 6

\frac{3}{50} + \frac{7}{30}

\frac{\frac{3}{a} + \frac{b}{6}}{\frac{2 b}{3 a}}

5 ∣ w + 4 ∣ \geq 15

- 1 < 9 + n < 17

1.2 5^{2}

What are the solutions to the equation (3y+9)^2=81 ?
The solutions to the equation (3y+9)^2=81 are y=0,y=-6
Find the zeros of (3y+9)^2=81
The zeros of (3y+9)^2=81 are y=0,y=-6